25^(x^2-2x)=(1/125)^(4x+2)

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Solution for 25^(x^2-2x)=(1/125)^(4x+2) equation: 



25^(x^2-2x)=(1/125)^(4x+2)

We move all terms to the left:

25^(x^2-2x)-((1/125)^(4x+2))=0



Domain of the equation: 125)^(4x+2))!=0

x∈R



We add all the numbers together, and all the variables

25^(x^2-2x)-((+1/125)^(4x+2))=0

We multiply all the terms by the denominator


(25^(x^2-2x))*125)^(4x+1+2))-((=0

We add all the numbers together, and all the variables

(25^(x^2-2x))*125)^(4x+3))-((=0

We add all the numbers together, and all the variables

(25^(x^2-2x))*125)^(4x=0

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